18x^2+36x-270=0

Solution for 18x^2+36x-270=0 equation:

18x^2+36x-270=0

a = 18; b = 36; c = -270;
Δ = b2-4ac
Δ = 362-4·18·(-270)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-144}{2*18}=\frac{-180}{36}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+144}{2*18}=\frac{108}{36}
=3
$